Andrewmabini7idn
Answered

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What is the probability that more than five pairs will be demanded in a particular day?

Sagot :

Kathreentordilidn

Answer:

Let P(M) and P(E) be the probability that a student takes mathematics, and the probability that a student takes English, respectively.

Thus, P(M)=10/30, P(E)=12/30, and [ P(M) and P(E)]=5/30.

If we want the probability that a student takes neither mathematics nor English, then we are looking for the set that is a compliment to [P(M) or P(E)].

That is, we want to find 1 - [P(M) or P(E)].

According to the Additive Law of Probability,

[P(M) or P(E)] = P(M) + P(E) - [P(M) and P(E)].

Thus,

[P(M) or P(E)] = 10/30 + 12/30 - 5/30

This equals 17/30.

Therefore, the compliment to [P(M) or P(E)] is

1 - 17/30 = 13/30.

There is an approximately 43% chance of choosing a student who is taking neither mathematics nor English.

Step-by-step explanation:

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