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Joseph's weight is 18.3 kg and his height is 103.5 cm. What is Joseph's BMI?

Sagot :

NobleOxfordidn

ANSWER :

  • ≈ 17.1

SOLUTION :

(18.3 kg ÷ 103.5 cm ÷ 103.5 cm) x 10,000

  • Convert the decimal into a fraction

(18.3/10 ÷ 103.5 ÷ 103.5) × 10000

(18.3/10 ÷ 207/2 ÷ 103.5) × 10000

(18.3/10 ÷ 207/2 ÷ 207/5) × 10000

  • Note : To divide by a fraction, multiply by the reciprocal of that fraction

(18.3/10 × 2/207 ÷ 2/207) × 10000

(18.3/10 × 2/207 × 2/207) × 10000

  • Reduce the numbers with the greatest common factor 2

(18.3/5 × 1/207 × 2/207) × 10000

  • Reduce the numbers with the greatest common factor 3

(61/5 × 1/69 × 2/207) × 10000

  • Multiply the fractions

122/71415 × 10000

  • Reduce the numbers with the greatest common factor 5

122/14283 × 2000

  • Multiply all

244000/14283

  • Then Convert fraction into decimal

244000 ÷ 14283

≈17.1

  • Therefore, Joseph Bmi is 17.1 and he's classification is Underweight.

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