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b. x(2x - 1)(x + 2) = 168,find the value of x?​

Sagot :

[tex] \large\underline \bold{{SOLUTION}}[/tex]

» Expand the binomials

[tex]\longmapsto\rm{x(2x-1)(x+2)=168}[/tex]

[tex]\longmapsto\rm{(2x²-x)(x+2)=168}[/tex]

[tex]\longmapsto\rm{2x³+4x²-x²-2x=168}[/tex]

[tex]\longmapsto\rm{2x³+3x²-2x=168}[/tex]

[tex]\longmapsto\rm{2x³+3x²-2x-168=0}[/tex]

» Factor the polynomial to get the roots

[tex]\longmapsto\rm{(x-4)(2x²+11x+42)=0}[/tex]

[tex]\longmapsto\rm{x-4=0 , \boxed{\sf{x=4}}}[/tex]

[tex] \large\underline{ \bold{ANSWER}}[/tex]

  • The value of x is 4