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GAY LUSSAC'S LAW (SHOW YOUR SOLUTION)
A gas occupies 237 mL at 760 torr and 40°C. When the pressure is changed to 510 torr, what temperature is needed to maintain the same volume?


Sagot :

Given:

[tex]P_{1} = \text{760 torr}[/tex]

[tex]T_{1} = \text{40°C + 273 = 313 K}[/tex]

[tex]P_{2} = \text{510 torr}[/tex]

Required:

[tex]T_{2}[/tex]

Solution:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

[tex]T_{2} = T_{1} × \frac{P_{2}}{P_{1}}[/tex]

[tex]T_{2} = \text{313 K} × \frac{\text{510 torr}}{\text{760 torr}}[/tex]

[tex]\boxed{T_{2} = \text{210 K}}[/tex]

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