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if neon gas travels at 400m/s at a given temperature, calculate the velocity of butane at the same temperature.


paanswer po pls thankyouuuu


Sagot :

Given:

[tex]v_{\text{neon}} = \text{400 m/s}[/tex]

Required:

[tex]v_{\text{butane}}[/tex]

Solution:

Step 1: Calculate the molecular weight of neon (Ne) and butane (C₄H₁₀).

For neon

[tex]MM_{\text{neon}} = \text{20.18 g/mol × 1}[/tex]

[tex]MM_{\text{neon}} = \text{20.18 g/mol}[/tex]

For butane

[tex]MM_{\text{neon}} = \text{(12.01 g/mol × 4) + (1.008 g/mol × 1)}[/tex]

[tex]MM_{\text{neon}} = \text{58.12 g/mol}[/tex]

Step 2: Calculate the velocity of butane.

[tex]\frac{v_{\text{butane}}}{v_{\text{neon}}} = \sqrt{\frac{MW_{\text{neon}}}{MW_{\text{butane}}}}[/tex]

[tex]v_{\text{butane}} = v_{\text{neon}}\sqrt{\frac{MW_{\text{neon}}}{MW_{\text{butane}}}}[/tex]

[tex]v_{\text{butane}} = (\text{400 m/s})(\sqrt{\frac{\text{20.18 g/mol}}{\text{58.12 g/mol}}})[/tex]

[tex]\boxed{v_{\text{butane}} = \text{235.7 m/s}}[/tex]

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