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Sagot :
the length of the pool is 15m while the width of the pool is 7m and having an area of 105m
We let the width be x, this would make the length x+8 so:
Area = length * width
105 = (x+8)x
105 = x²+8x
0 = x²+8x-105
Method 1: Guess and Check
We look for two numbers with a product of 105 and an absolute difference of 8.
105 - 1 = 104 X
35 - 3 = 32 X
21 - 5 = 16 X
15 - 7 = 8 √
Therefore:
0 = (x+15)(x-7)
So the possible value of x are -15 and 7. We cannot have a negative value since a length is never negative.
Method 2: Quadratic Formula
x = -8 ± √(8²+420) = -8 ± √484 = -8 ± 22 = -15 or 7
2 2 2
Again we cannot have a negative length so we only consider 7.
So the width is 7m and the length is 15m.
Area = length * width
105 = (x+8)x
105 = x²+8x
0 = x²+8x-105
Method 1: Guess and Check
We look for two numbers with a product of 105 and an absolute difference of 8.
105 - 1 = 104 X
35 - 3 = 32 X
21 - 5 = 16 X
15 - 7 = 8 √
Therefore:
0 = (x+15)(x-7)
So the possible value of x are -15 and 7. We cannot have a negative value since a length is never negative.
Method 2: Quadratic Formula
x = -8 ± √(8²+420) = -8 ± √484 = -8 ± 22 = -15 or 7
2 2 2
Again we cannot have a negative length so we only consider 7.
So the width is 7m and the length is 15m.
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