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First, finding the constant of the variation
[tex]x = \frac{ky}{z} \\ 30 = \frac{k(40)}{80} \\ {40} = \frac{k}{2} \\ 40(2) = k \\ 80 = k[/tex]
Then , finding for the unknown variable to a given condition
[tex]x = \frac{ky}{z} \\ x = \frac {24(80)}{60} \\ x = \frac{24(4)}{3} \\ x = \frac{\cancel{24} \: ^{8} (4)}{ \cancel {3} \: ^{1} } \\ x = 8(4) \\ x = 32[/tex]
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