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Sagot :
Answer:
This is the general standard equation for the circle centered at (\blueD h, \maroonD k)(h,k)left parenthesis, start color #11accd, h, end color #11accd, comma, start color #ca337c, k, end color #ca337c, right parenthesis with radius \goldD rrstart color #e07d10, r, end color #e07d10.
Circles can also be given in expanded form, which is simply the result of expanding the binomial squares in the standard form and combining like terms.
For example, the equation of the circle centered at (\blueD 1,\maroonD 2)(1,2)left parenthesis, start color #11accd, 1, end color #11accd, comma, start color #ca337c, 2, end color #ca337c, right parenthesis with radius \goldD 33start color #e07d10, 3, end color #e07d10 is (x-\blueD 1)^2+(y-\maroonD 2)^2=\goldD 3^2(x−1)
2
+(y−2)
2
=3
2
left parenthesis, x, minus, start color #11accd, 1, end color #11accd, right parenthesis, squared, plus, left parenthesis, y, minus, start color #ca337c, 2, end color #ca337c, right parenthesis, squared, equals, start color #e07d10, 3, end color #e07d10, squared. This is its expanded equation:
\begin{aligned} (x-\blueD 1)^2+(y-\maroonD 2)^2&=\goldD 3^2 \\\\ (x^2-2x+1)+(y^2-4y+4)&=9 \\\\ x^2+y^2-2x-4y-4&=0 \end{aligned}
(x−1)
2
+(y−2)
2
(x
2
−2x+1)+(y
2
−4y+4)
x
2
+y
2
−2x−4y−4
=3
2
=9
=0
Want to learn more about circle equations? Check out this video.
Practice set 1: Using the standard equation of circles
PROBLEM 1.1
(x+4)^{2}+(y-6)^{2} = 48(x+4)
2
+(y−6)
2
=48left parenthesis, x, plus, 4, right parenthesis, squared, plus, left parenthesis, y, minus, 6, right parenthesis, squared, equals, 48
What is the center of the circle?
((left parenthesis
,,comma
))right parenthesis
What is its radius?
If necessary, round your answer to two decimal places.
units
Explain
Want to try more problems like this? Check out this exercise and this exercise.
Practice set 2: Writing circle equations
PROBLEM 2.1
A circle has a radius of \sqrt{13}
13
square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)left parenthesis, minus, 9, point, 3, comma, 4, point, 1, right parenthesis.
Write the equation of this circle.
Explain
Want to try more problems like this? Check out this exercise.
Practice set 3: Using the expanded equation of circles
To interpret the expanded equation of a circle, we should rewrite it in standard form using the method of "completing the square."
Consider, for example, the process of rewriting the expanded equation x^2+y^2+18x+14y+105=0x
2
+y
2
+18x+14y+105=0x, squared, plus, y, squared, plus, 18, x, plus, 14, y, plus, 105, equals, 0 in standard form:
\begin{aligned} x^2+y^2+18x+14y+105&=0 \\\\ x^2+y^2+18x+14y&=-105 \\\\ (x^2+18x)+(y^2+14y)&=-105 \\\\ (x^2+18x\redD{+81})+(y^2+14y\blueD{+49})&=-105\redD{+81}\blueD{+49} \\\\ (x+\redD9)^2+(y+\blueD7)^2&=25 \\\\ (x-(-9))^2+(y-(-7))^2&=5^2 \end{aligned}
x
2
+y
2
+18x+14y+105
x
2
+y
2
+18x+14y
(x
2
+18x)+(y
2
+14y)
(x
2
+18x+81)+(y
2
+14y+49)
(x+9)
2
+(y+7)
2
(x−(−9))
2
+(y−(−7))
2
=0
=−105
=−105
=−105+81+49
=25
=5
2
Now we can tell that the center of the circle is (-9,-7)(−9,−7)left parenthesis, minus, 9, comma, minus, 7, right parenthesis and the radius is 555.
PROBLEM 3.1
x^2+y^2-10x-16y+53=0x
2
+y
2
−10x−16y+53=0x, squared, plus, y, squared, minus, 10, x, minus, 16, y, plus, 53, equals, 0
What is the center of this circle?
((left parenthesis
,,comma
))right parenthesis
What is the radius of this circle?
units
Explain
Want to try more problems like this? Check out this exercise and this exercise.
Are yo
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