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What no. Exceeds its squared by the maximum amount?

Sagot :

Note that:
[tex]x^2 \geq 0[/tex]
This is for any real number x.

Also a number is always less than its square unless it is equal to 0 (because this would make the square 0 as well) so for the number to exceed its square by the maximum amount that number needs to be 0, because this will make their difference be 0.