The first diagonal-x
The second diagonal-y
y=2x
because it says one diagonal is twice the other
x+y=24
The sum of the length of the diagonals is 24. Therefore substitute the value of y.
x+2x=24
Add like terms
3x=24
Divide both sides by 3
x=8
Therefore the first diagonal is 8 and the second is 16. Now the formula for the area of the rhombus given its diagonals is:
[tex]A=\frac{pq}{2}[/tex]
Substitute the diagonals
[tex]A=\frac{(8)(16)}{2}[/tex]
[tex]A=\frac{128}{2}[/tex]
A=64 sqr. units
The area is 64 sqr. units. Hope this helps =)
