Hazelmaeidn
Answered

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one of the diagonals of a rhombus is twice as the other.if the sum of the lengths of the diagonals is 24, find the area of the rhombus

Sagot :

Jers15idn
The first diagonal-x
The second diagonal-y

y=2x
because it says one diagonal is twice the other
x+y=24
The sum of the length of the diagonals is 24. Therefore substitute the value of y.
x+2x=24
Add like terms
3x=24
Divide both sides by 3
x=8

Therefore the first diagonal is 8 and the second is 16. Now the formula for the area of the rhombus given its diagonals is:
[tex]A=\frac{pq}{2}[/tex]
Substitute the diagonals
[tex]A=\frac{(8)(16)}{2}[/tex]
[tex]A=\frac{128}{2}[/tex]
A=64 sqr. units

The area is 64 sqr. units. Hope this helps =)