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1.Find 4 consecutive odd integers whose sum is 248

Sagot :

Note that the difference between two odd integers is 2. For example, the difference between  1 and 3 is 2.

Let [tex]x[/tex] be the first odd integer. Then the next three odd integers are:
[tex]x+2, (x+2)+2, [(x+2)+2]+2[/tex]. The sum of these 4 consecutive integers, written in symbols:
[tex]x +x+2 +(x+2)+2 +[(x+2)+2]+2 = 248[/tex]
Simplying, we have
[tex]4x +12 = 248[/tex] which gives [tex]x = 59[/tex].
Therefore, the four consecutive odd integers are
[tex]59,61,63,65[/tex]