let x+7y=23 be our equation 1
let 12x+11y=23 be our equation 2
x+7y=23
12x+11y=23
Multiply ‐12 to our equation 1 and we get
‐12x‐84y=‐276 ‐‐‐‐‐‐> let ‐12x‐84y=‐276 be our equation 3.
now let's add equations 2 and 3
12x+11y=23
+
‐12x‐84y=‐276
we get
‐73y = ‐253
Divide both sides by ‐73 and we get the value of y
y=253/73
Let us substitute the value of y in equation 2.
12x + 11(253/73) = 23
12x +2583/73 = 23
12x = (‐2583/73) +23
12x = ‐1104/73
divide both sides by 12 and we get the value of x
x= ‐92/73
Therefore, y = 253/73 and x = ‐92/73