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Sagot :
suppose you have the expression as:
[tex] \frac{x^2}{x^2} [/tex]
isn't it that the law of exponent states that
[tex] \frac{a^n}{a^m} =a ^{m-n} [/tex]
then that makes the expression
[tex] x^{2-2} = x^0[/tex]
isn't it that when you divide x² by x² directly you'll get 1?
now let's have this sequence
2³ = 8
2² = 4
[tex]2^1 = 2[/tex]
[tex]2^0 = 1[/tex]
did you notice that when you subtract the exponent from cube to square(3-1), it's just 8/2=4? it's the same thing happened when you have exponents 1 and 0 from exponent 1 2^1 = 2 since you are to get the value for the number raised to zero then all you have to do is divide 2 by 2 = 1
[tex] \frac{x^2}{x^2} [/tex]
isn't it that the law of exponent states that
[tex] \frac{a^n}{a^m} =a ^{m-n} [/tex]
then that makes the expression
[tex] x^{2-2} = x^0[/tex]
isn't it that when you divide x² by x² directly you'll get 1?
now let's have this sequence
2³ = 8
2² = 4
[tex]2^1 = 2[/tex]
[tex]2^0 = 1[/tex]
did you notice that when you subtract the exponent from cube to square(3-1), it's just 8/2=4? it's the same thing happened when you have exponents 1 and 0 from exponent 1 2^1 = 2 since you are to get the value for the number raised to zero then all you have to do is divide 2 by 2 = 1
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