To factor that out,
you should transform that first into standard form.
which is
ax² + bx + c
then locate the three numbers. (a,b,& c)
Let's see...
That would be -10x²+11x+6 (always put in detail their signs)
so now,
a = -10
b = 11
c = 6
And then, two start off, you have to find ac
meaning, the product of "a" and "c" and that would be??
I'll wait for your reply, let's answer it together.
-----
ac = -60
then find the factors of -60, which when added together becomes b.
Let's say the factors are
-4, & 15
or
-15, & 4
then add them together...
-15 + 4 = -11
or
-4 + 15 = 11 "Ding! we have a winner!"
btw we can also look at it as, 15 +(-4) = 11 or 15-4 = 11
So now we can say that
15x - 4x = 11x now substitute the factors into the equation
-10x² +15x - 4x + 6 group the 2 terms on the left, and the 2 terms on the right.
(-10x² +15x)+(-4x+6) and then simply factor out both.
-5x( 2x - 3) + (-2)(2x - 3)
-5x( 2x-3) -2(2x - 3) simplify the common multiple, "(2x-3)"
"(-5x-2)(2x-3)"
I believe we're done. I hope it was clear, this is like my first serious answer. :D