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1) If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature
of 200. K, and then I raise the pressure to 14.0 atm and increase the temperature to 300. K,
what is the new volume of the gas?
2) A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of 299
K. If I raise the temperature to 350 K and lower the pressure to 1050 mmHg, what is the
new volume of the gas?
3)
A gas that has a volume of 28 liters, a temperature of 65 °C, and an unknown pressure has
its volume increased to 36 liters and its temperature decreased to 35 °C. If I measure the
pressure after the change to be 2.0 atm, what was the original pressure of the gas?

Sagot :

Answer:

1. 25.71 L

2. 49.78 L

3. 2.82 atm

Explanation:

use the ideal gas law formula where the number of molecule is constant,

(P1V1)/T1 = (P2V2)/T2

for the new volume, it would become

(P1V1T2)/(T1P2) = V2

for the original pressure

P1 = (P2V2T1)/(T2V1)