If BD = DC, then 70 degrees is a base angle of Isosceles ΔBCD
∠ BCD and ∠CBD are base angles. Therefore, each base angle measures 70 degrees.
To find the third angle ∠BDC:
m∠BDC = 180 - [ m∠BCD + m∠CBD ]
m∠BDC = 180° - [ 70° + 70° ]
m∠BDC = 180° - 140°
m∠BDC = 40°
∠BDC and ∠ADB are supplementary angles. To find the measure of ∠ADB:
m∠ADB = 180° - m∠BDC
m∠ADB = 180° - 40°
m∠ADB = 140°
The degree measure of ∠ADB is 140°