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the length of a rectangle is 13 inches greater than its width,its perimeter is 8 feet.Find its dimension

Sagot :

let x=length and y=width
equations: 1st= x= 13 + y and P= 2x+2y
substitute: 8 ft = 96 inches
96=2(13 + y) + 2y
96=26 + 4y
4y=96-26
y=17.50
substitute y to first equation.
x=30.50

the dimensions of the rectangle are 30.50 inch by 17.50 inch. :)