[tex]Let's\ get\ the\ value\ of\ x\ to\ solve\ the\ second\ equation. \\ \\ Solution; \\ 8x+12=24 \\ \\ 8x=24-12 \\ \\ \frac{8x}{8}=\frac{12}{8} \\ \\ \boxed{x= \frac{3}{2}} \\ \\ Let's\ substitute\ x\to \frac{3}{2} \\ \\ Solution; \\ 24x+36 \\ \\ 24( \frac{3}{2})+36 \\ \\ \frac{72}{2}+36 \\ \\ 36+36\to\boxed{\boxed{72}} \\ \\ Hope\ it\ Helps:) \\ Domini [/tex]
