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Sagot :
Let 'x' be the first number
'y' be the other number
----------------------------
-when added is 114
x + y = 114 ----equation 1
----------------------------
-when subtracted is 58
x - y = 58 ----equation 2
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From equation 2
x - y = 58
x = y + 58 ----equation 2'
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Substitute equation 2' to equation 1
x + y = 114
y + 58 + y = 114
y + y = 114 - 58
2y = 56
y = 28
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Substitute y=28 to equation 2'
x = y + 58
x = 28 + 58
x = 86
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Therefore the two numbers are 28 and 86.
'y' be the other number
----------------------------
-when added is 114
x + y = 114 ----equation 1
----------------------------
-when subtracted is 58
x - y = 58 ----equation 2
---------------------------
From equation 2
x - y = 58
x = y + 58 ----equation 2'
---------------------------
Substitute equation 2' to equation 1
x + y = 114
y + 58 + y = 114
y + y = 114 - 58
2y = 56
y = 28
--------------------------
Substitute y=28 to equation 2'
x = y + 58
x = 28 + 58
x = 86
------------------------
Therefore the two numbers are 28 and 86.
[tex]Let\ x\ be\ the\ first\ unknown\ number \\ Let\ y\ be\ the\ second\ unknown\ number \\ \\ x+y=114\to\boxed{equation\ 1} \\ x-y=58\to\boxed{equation\ 2} \\ \\ Let's\ use\ Elimination\ Method; \\ \\ x+y=114 \\ x-y=58 \\ \\ \boxed{x=172} \\ \\ Solved\ for\ y\ by\ using\ Equation\ 1. \\ Let\ x\to172 \\ \\ x+y=114 \\ \\ 172+y=114 \\ \\ y=114-172 \\ \\ \boxed{-58} \\ \\ Therefore,the\ 2\ numbers\ are\ \underline{172}\ and\ \underline{-58} \\ \\ Hope\ it\ Helps:) \\ Domini[/tex]
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