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Evaluating Algebraic Expressions. What will we do if the give is like this x2 – 8x, do we have to make it multiplication, because the operation symbol will be the sign of the 8, or we will evaluate t like we evaluating integers?
I am not sure, but if you mean how to answer, x2-8x, then, this is how to answer that equation. In the law of Algebra, the constant always comes first before the variable, so it should be that x2 is 2x using the law, so lets answer.
2x-8x=(just think of it like fractions wherein in fractions you copy the same denominator, but here, in this equation, you copy x. Just think that it is 2-8, then copy x) 2x-8x =-6x -6x + 8x= 2, true Therefore you do this equation like they are integers and copy x.
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