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Logarithm po ito siya nah problem


Logarithm Po Ito Siya Nah Problem class=

Sagot :

Answer:

x = -8 ,  x = 5

Step-by-step explanation:

Applying logarithmic rule

[tex]log_{a}b = x\\b = a^{x}[/tex]

If a > 0 and a ≠ 1 then logarithm of a positive number b is defined as b equal to a raised to x

[tex]2=\log _7(x^2+3x+9)\\7^{2} = x^2+3x+9\\49=x^2+3x+9\\x^2+3x+9- 49 = 0\\x^2+3x-40 = 0\\\text {Factor completely}\\(x+8)(x-5) = 0[/tex]

Equating to zero

x+8 = 0     ; x - 5 =0

x = -8        ; x = 5

Therefore the answer is x = -8 ,  x = 5

Checking

Substituting x = -8

[tex]2=\log _7(64-24+9) \\2=2[/tex]

Substituting the value of x = 5

[tex]2=\log _7(25+15+9) \\2=2[/tex]

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