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Half the perimeter of a rectangle is 51 cm. If the difference between the length and the wind is 13 cm, what is the area of the rectangle?​

Sagot :

P=51x2

P=102

Let x= Length

" x-13 = Width

102= 2(x) + 2(x-13)

102= 2x + 2x -26

4x-26-102

4x-128

4x/4 =128/4

x=32

Length=32

width:

x-13

32-13=19

w=19

A= LxW

A= 32x19

A= 608