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Given:
[tex]G=6.67 ×10 ^{ −11} \: N⋅m^{2}/kg^{2}[/tex]
[tex]r = 0.750 \: m[/tex]
[tex]m_1=m_2= 5.00 \: kg[/tex]
Required:
Gravitational Force
Equation:
[tex]F_{g} = \frac{{Gm_{1}m_{2}}}{r^{2}}[/tex]
[tex] Where: F_g = Gravitational \:Force, \:N[/tex]
[tex] G = Gravitational \:constant,[/tex]
[tex] G=6.67 ×10 ^{ −11} \: N⋅m^{2}/kg^{2}[/tex]
[tex] m_1, m_2 = mass \:of \:objects,\: kg[/tex]
[tex] r = distance \:between \:the\: objects, \:m [/tex]
Solution:
[tex]F_g = \frac{(6.67 \times 10^{-11} N \cdot m^{2}/ kg^ {2}) (5.00 kg) (5.00 kg)}{(0.750 m)^{2}}[/tex]
[tex]F_g = \frac{(6.67 \times 10^{-11} N \cdot m^{2}/ kg^ {2}) (25.00 \: kg^2)}{0.5625 \: m^{2}}[/tex]
[tex]F_g = 296.44 \: \times 10^{ - 11}N[/tex]
[tex]F_g = 2.9644 \: \times 10^{ - 9}N[/tex]
Final Answer:
[tex]The\: Gravitational\: Force\: is\: 2.9644 \: \times 10^{ - 9}N[/tex]
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