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Learning Task 2.
Choose two ordered pair that will satisfy the inequality
1. y < x + 3 ; (2,5), (5, 2), (-5, -5), (4,0)
2. 3x + y > 10; (-1, 2), (1, 10), (3, 1), (3, 3)
2y + x 2 5; (1, 2), (0,4), (2,2), (-1.-5)
4. 3x - 2y s 10; (5,1), (0,-5), (-1, -6), (10, 2)
5. 5x + 3y > 15; (2,1), (-3, 1), (0, 6), (2, 2)​


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Sagot :

Answer:

To “satisfy an inequality” means to show that substituting one or more variables into an inequality proves that the statement is true.

1. (5,2) and (-5,-5) or (4,0)

2. (1,10) and (3,3)

3. (1,2) and (0,4) or (2,2)

4. (0,-5) and (-1,-6)  

5. (0,6) and (2,2)

Step-by-step explanation:

Substitute the values of x and y from the given ordered pairs to check if the inequality is true.

1. If x = 5 and y = 2

2 < 5+3

2 < 8  

The inequality is true.

If x = -5 and y = -5  

-5 < -5 + 3

-5 < -2  

The inequality is true.

If x = 4 and y = 0

0 < 4 + 3

0 < 7  

The inequality is true.

2. If x = 1 and y = 10

3(1) + 10 > 10

3 + 10 > 10

13 > 10

The inequality is true.

If x = 3 and y = 3

3(3) + 3 > 10

9 + 3 > 10

12 > 10

The inequality is true.

3. If x = 1 and y = 2

2(2) + 1 ≥ 5

4 + 1 ≥ 5

5 ≥ 5

The inequality is true.

If x = 0 and y = 4

2(4) + 0 ≥ 5

8 + 0 ≥ 5

8 ≥ 5

The inequality is true.

If x = 2 and y = 2

2(2) + 2 ≥ 5

4 + 2 ≥ 5

6 ≥ 5

The inequality is true.

4. If x = 0 and y = -5

3(0) – 2(-5) ≤ 10

0 + 10 ≤ 10

10 ≤ 10

The inequality is true.

If x = -1 and y = -6

3(-1) – 2(-6) ≤ 10

-3 + 12 ≤ 10

9 ≤ 10

The inequality is true.

5. If x = 0 and y = 6

5(0) + 3(6) > 15

0 + 18 > 15

The inequality is true.

If x = 2 and y = 2

5(2) + 3(2) > 15

10 + 6 > 15

16 > 15

The inequality is true.

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