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A long-distance runner started a course running at an average speed of 6mph. One and one-half hours later, a cyclist traveled the same course at an average speed of 12mph. How long after the runner started did the cyclist overtake the runner?

Sagot :

Answer:

3hrs

Step-by-step explanation:

6(t+1.5)=12t

6t+9=12t

3/2 or 1.5 =t

1.5+1.5 = t+1.5

3