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The length of a rectangle is 1200 cm and its width is 900 cm. If the length is
decreased by 3/20 and the width is increased by 1/5. Find the area of the new
rectangle.​

Sagot :

Hanzysomera88idn

Problem:

The length of a rectangle is 1200 cm and its width is 900 cm. If the length is decreased by 3/20 and the width is increased by 1/5. Find the area of the new rectangle.

Solution:

Find the new length:

[tex]1200 - 1200 \times \frac{3}{20}[/tex]

[tex] = 1200 - 60 \times \frac{3}{1} [/tex]

[tex] = 1200 - \frac{180}{1} [/tex]

[tex] = 1200 - 180[/tex]

[tex] = 1020[/tex]

Find the new width:

[tex]900 + 900 \times \frac{1}{5} [/tex]

[tex] = 900 + 180 \times \frac{1}{1} [/tex]

[tex] = 900 + \frac{180}{1} [/tex]

[tex] = 900 + 180[/tex]

[tex] = 1080[/tex]

Find the new area:

[tex]1020 \times 1080[/tex]

[tex] = 1101600[/tex]

Answer:

1,101,600 square cm

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