Lynncuibillasidn
Answered

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27b³-1=(3b-___) (____+3b+1)​

Sagot :

Hurgfsidn

Answer:

1 for the first blank and

[tex]9b^2[/tex] for the second blank.

Step-by-step explanation:

By observation 27b³-1 is a perfect cube

27b³ = (3b)³

1 = 1³

Operation used is " - "

Therefore the problem is all about the difference of perfect cubes

Where:

[tex]a^3 - b^3 = (a - b)(a^2 + ab + b^2)[/tex]

Solving:

a = 3b

b = 1

Substituting the value of a and b

[tex]27b^3 - 1^3 = (3b - 1)((3b)^2 + 3b(1) + 1^2) \\27b^3 - 1^3 = (3b - 1)(9b^2 + 3b + 1^2)[/tex]

Therefore the answer is

1 for the first blank and

[tex]9b^2[/tex] for the second blank.

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