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Math 6 Module 5 Assessment ​

Math 6 Module 5 Assessment class=

Sagot :

MULTIPLE CHOICE

Item 10.

Question:

  • What is the quotient for [tex]4\dfrac{3}{6}[/tex] and [tex]1\dfrac{2}{3}[/tex]?

Choices:

    [tex]\begin{aligned}\text{A. } & 4\dfrac{7}{10} & \text{B. } & 2\dfrac{1}{8} & \text{C. } & 2\dfrac{7}{10} & \text{D. } 4\dfrac{1}{8} \end{aligned}[/tex]

Solution:

    [tex]\begin{aligned}4\dfrac{3}{6} \div 1\dfrac{2}{3} = \dfrac{27}{6} \div \dfrac{5}{3} = \dfrac{27}{6} \times \dfrac{3}{5} = \dfrac{81}{30} \Rightarrow \dfrac{27}{10} = 2\dfrac{7}{10} \end{aligned}[/tex].

Step-by-step explanation:

  1. Convert mixed number into improper fraction.
  2. Find the reciprocal of the divisor to change the operation into multiplication symbol.
  3. Multiply the two fractional factors.
  4. Reduce (if possible). Then, convert the improper fraction into mixed form of a fraction if possible.

Answer:

  • [tex]\text {C. } 2\dfrac{7}{10}[/tex]

Mathematics 6 Module 5

Pre-assessment: Multiple Choice (Item 1-4): brainly.ph/question/8785116

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Note: The answer is correct.