Answer:
[tex]$ \mbox{\Large$ 6x^2 + 4x + 3 = 0$ } $[/tex]
Step-by-step explanation:
1.) The standard form of a quadratic function is [tex]ax^2 + bx + c = 0[/tex], where [tex]a, b, c[/tex] are all constants and [tex]x[/tex] is a variable.
2.) In this problem, we can transpose or transfer all of the terms to one side of the equation and leave the other side equal to [tex]0[/tex]. In this case, it is the constant [tex]-3[/tex] on the Right Hand Side of the equation that we need to transpose.
⇒ [tex]$ \mbox{\Large$ 4x + 6x^2 = -3$ } $[/tex]
⇒ [tex]$ \mbox{\Large$ 4x + 6x^2 + (3)= -3 + (3)$ } $[/tex]
⇒ [tex]$ \mbox{\Large$ 4x + 6x^2 + 3 = 0$ } $[/tex]
⇒ [tex]$ \mbox{\Large$ \bold{6x^2 + 4x + 3 = 0}$ } $[/tex]
3.) Therefore, the standard form of the quadratic function [tex]4x + 6x^2 = -3[/tex] is [tex]6x^2 + 4x + 3 = 0[/tex].
I hope this helps you understand this concept in Mathematics.
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