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graph 2x+y=-3 in system of linear equation in two variables


Sagot :

[tex]A \ linear \ equation \ is \ an \ equation \ for \ a \ straight \ line :\\\\y=ax+b \\\\2x+y=-3 \ \ | \ add\ 2x\ to\ both\ sides \\y=-2x-3 \\\\ the \ intersection \ with \ y-axis\\ x=0 \ \to\ y=-2*0-3=-3 \\\\the \ intersection \ with \ x-axis\\ y=0 \ \to\ 0=-2x-3\\2x=-3\ \ | \ divide \ both \ sides\ by\ 2 \\\\x=-\frac{3}{2}=-1.5 [/tex]

View image Riza1
Sol'n:
 The graph of the equation 2x + y = -3 is a straigth line.
the formula is;
y=mx+b
        where 'm' is the slope
                 'b' is the y intercept.
To graph of this equation you can also trial and error.Assign the vaue of either X or Y by Zero .Say,
 y=-2x-3     ------that is the equation above.Im just only into the form above.
Let:                                    Let:
Y=0                                         X=0
0=-2X-3                                    Y=2(0)-3
X=-3/2                                      Y=-3
(-3/2,0)                                      (0,-3)
Therefore the coordinates are:
(-3/2,0) & (0,-3)
Then, plot on the Cartesian plane.

Hope it helps.:) 
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