Bea6idn
Answered

IDNStudy.com, ang iyong mapagkukunan para sa malinaw at maaasahang mga sagot. Tuklasin ang mga kumpletong sagot sa iyong mga tanong mula sa aming komunidad ng mga eksperto.

THE 2ND NO. IS 1 MORE THAN TWICE OF THE THIRD NO. AND THE FIRST NO. IS EIGHT MORE THAN 3X OF THE SECOND NO.IF THERE SUM IS 129, WHAT IS THE LARGEST NO.

Sagot :

Tgf45idn
X-First number
Y-Second Number
Z-Third number

Y=1 + 2z
x=8 + 3y
x + y+ z = 129

Solving the three equations:
X=89
Y=27
Z=13

Therefore the answer is X=89.
Shinalcantaraidn
Let 'x' be the 1st number
      'y' be the 2nd number
     'z' be the 3rd number
--------------------------------
-The 2nd number is 1 more than twice the third number
y = 2z + 1   -----equation 1
-------------------------------
-The 1st number is 8 more than thrice of the 2nd
x = 3y + 8  -----equation 2
------------------------------
-Their sum is 129
x + y + z = 129   ---equation 3
-----------------------------
Expressing everything in terms of y, you'll have:
From equation 1
y = 2z + 1
2z = y - 1
z = (y-1)/2  ------equation 1'
----------------------------
Substitute equations 1' and 2 to equation 3
x + y + z =129
(3y+8) + y + (y-1)/2 = 129
Multiply the whole equation with 2
6y + 16 + 2y + y - 1 = 258
6y + 2y + y = 258 + 1 - 16
9y = 243
y = 27
--------------------------
Substitute y=27 to equation 1'
z = (y-1)/2
z = (27-1)/2
z = 26/2
z = 13
--------------------------
Substitute y=27 to equation 2
x = 3y + 8
x = 3(27) + 8
x = 81 + 8
x = 89
--------------------------
Therefore the largest number is 89.
Ang iyong kontribusyon ay mahalaga sa amin. Huwag kalimutang bumalik upang magtanong at matuto ng mga bagong bagay. Ang iyong kaalaman ay napakahalaga sa ating komunidad. Salamat sa pagbisita sa IDNStudy.com. Nandito kami upang magbigay ng malinaw at tumpak na mga sagot.