Sumali sa IDNStudy.com at tuklasin ang komunidad ng pagbabahagi ng kaalaman. Ang aming komunidad ay handang magbigay ng malalim at maaasahang mga sagot, anuman ang kahirapan ng iyong mga katanungan.
A 0.50 kg ball is moving with a velocity of 8.0 m/s along a horizontal floor. It hits another ball with a mass of 0.80 kg and moving at 10.0 m/s in the opposite direction. If the first ball bounces back with a velocity of 12 m/s, with what velocity and in what direction will the second ball go after collision?
I think this is about elastic collision so use the formula m1vi1 + m2vi2 = m1vf1 + m2vf2, so the given in this problem is: m1 = 0.5kg vi1 (initial velocity 1) = 8m/s vf1 (final velocity of 1st ball= 12 m/s m2= 0.8kg vi2= 10m/s vf2 = (what you're looking for)
so just input the values on your calculator and you're done:)
also for the direction, i think it's dependent on the sign of the answer:)))))
Natutuwa kami na ikaw ay bahagi ng aming komunidad. Huwag kalimutang bumalik upang magtanong at magbahagi ng iyong karanasan. Ang iyong kaalaman ay mahalaga sa ating komunidad. Bawat tanong ay may sagot sa IDNStudy.com. Salamat at sa muling pagkikita para sa mas maraming solusyon.
