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Sagot :
x=larger
y=smaller
x+y=28
x=2y-5
Substitution
2y-5+y=28
3y-5=28
3y=33
y=11
Substitute again to find value of x
x+y=28
x+11=28
x=17
y=smaller
x+y=28
x=2y-5
Substitution
2y-5+y=28
3y-5=28
3y=33
y=11
Substitute again to find value of x
x+y=28
x+11=28
x=17
Let x and y be the numbers
l is the Larger
s is the Smaller
l + s = 28
Larger is 5 less than twice the smaller
l = 2s - 5
Substitute value of l
2s - 5 + s = 28
Add
3s - 5 = 28
Transpose -5
3s = 28 + 5
Add
3s = 33
Divide by 3
s = 11
Substitute the value of s to the 1st equation
l + 11 = 28
Transpose 11
l = 28 - 11
Therefore
l = 17
I hope it helps
l is the Larger
s is the Smaller
l + s = 28
Larger is 5 less than twice the smaller
l = 2s - 5
Substitute value of l
2s - 5 + s = 28
Add
3s - 5 = 28
Transpose -5
3s = 28 + 5
Add
3s = 33
Divide by 3
s = 11
Substitute the value of s to the 1st equation
l + 11 = 28
Transpose 11
l = 28 - 11
Therefore
l = 17
I hope it helps
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