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Sagot :
Neither is the fastest, the average speed is the same
Further explanation
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
d = v x t
d = displacement
for average speed :
[tex]\boxed{\bold{v_{avg}=\dfrac{total~distance}{total~time}}}[/tex]
Given
The first person = covered 10 m in 5 seconds
The second person = covered 20 m in 10 seconds
Required
who is the fastest
Solution
The average speed of each person :
- first person
v avg = 10 m : 5 s = 2 m/s
- second person
v avg = 20 m : 10 s = 2 m/s
Both have the same average speed, so neither is the fastest
Learn more
uniformly accelerated motion
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the probe’s velocity relative to the earth
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Uniformly accelerated motion
brainly.ph/question/2098492
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