Kathhidn
Answered

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suppose that ax^2 + 3x + c is divided by x+1 and the remainder is 0. if a is twice c, what are the values of a and c?

Sagot :

[tex]ax^2 + 3x + c = 0[/tex]
if a = 2c  and zero is the remainder when divided by x+1.
using remainder's theorem, we will plug in the value of x as
x+1 = 0
x = -1
[tex]ax^2 + 3x + c = 0[/tex]
[tex]a(-1)^2 + 3(-1) + c = 0[/tex]
[tex]a - 3 + c = 0[/tex]
since a = 2c
[tex]2c - 3 + c = 0[/tex]
[tex]3c = 3[/tex]
[tex]c = 1[/tex]
substitute c = 1 to   a=2c
[tex]a = 2c[/tex]
[tex]a = 2(1)[/tex]
[tex]a = 2[/tex]