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in a scene from a movie or superman, he was shown running after a train. the train moves at 54 m/s. how much work must he do to stop the train if the mass of the train is 425000 kg?



Sagot :

Answer:

The work to stop the train is 6.197 x 10 J.

Explanation:

Here, we are to solve for the work to stop a train. We are to connect work with a given mass and velocity.

To solve this, we are to use the work-energy principle. Since there is a net force of work doing on the train, the kinetic energy of the moving train will be equal to work done.

Therefore. we will be using the formula:

W = ΔKE

W = KE₂ - KE₁

W = (¹/₂mv²)₂ - (¹/₂mv²)₁

where

W     is the work done on the train

m     is the mass of the train

v       is the velocity of the train

KE₂  is the final kinetic energy

KE₁   is the initial kinetic energy

For the given information

v = 54 m/s

m = 425,000 kg

W = ?

Solving the problem

So, let us solve for the work done on the train by using the work-energy formula.

Here, let us assume that the initial kinetic is zero.

W = ΔKE

W = KE₂ - KE₁

W = (¹/₂mv²)₂ - (¹/₂mv²)₁

Substitute the given information, we have:

W = ¹/₂(425000 kg)(54 m/s)²

W = 619,650,000 J   or

W = 6.197 x 10J

Therefore, the work done on the train to stop it is 6.197 x 10J.

To learn more about this topic, just click on the following links:

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