Makakuha ng mabilis at eksaktong mga sagot sa IDNStudy.com. Ang aming komunidad ay handang magbigay ng malalim at praktikal na mga solusyon sa lahat ng iyong mga katanungan.
Sagot :
Answer:
The work to stop the train is 6.197 x 10⁸ J.
Explanation:
Here, we are to solve for the work to stop a train. We are to connect work with a given mass and velocity.
To solve this, we are to use the work-energy principle. Since there is a net force of work doing on the train, the kinetic energy of the moving train will be equal to work done.
Therefore. we will be using the formula:
W = ΔKE
W = KE₂ - KE₁
W = (¹/₂mv²)₂ - (¹/₂mv²)₁
where
W is the work done on the train
m is the mass of the train
v is the velocity of the train
KE₂ is the final kinetic energy
KE₁ is the initial kinetic energy
For the given information
v = 54 m/s
m = 425,000 kg
W = ?
Solving the problem
So, let us solve for the work done on the train by using the work-energy formula.
Here, let us assume that the initial kinetic is zero.
W = ΔKE
W = KE₂ - KE₁
W = (¹/₂mv²)₂ - (¹/₂mv²)₁
Substitute the given information, we have:
W = ¹/₂(425000 kg)(54 m/s)²
W = 619,650,000 J or
W = 6.197 x 10⁸ J
Therefore, the work done on the train to stop it is 6.197 x 10⁸ J.
To learn more about this topic, just click on the following links:
- Relationship of work, energy and power
https://brainly.ph/question/160947
- Additional example with solution and answer
https://brainly.ph/question/2267052
#LetsStudy
Ang iyong presensya ay mahalaga sa amin. Patuloy na magbahagi ng iyong karanasan at kaalaman. Ang iyong ambag ay napakahalaga sa aming komunidad. Salamat sa pagbisita sa IDNStudy.com. Bumalik ka ulit para sa mga sagot sa iyong mga katanungan.