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Sagot :
Answer:
The work to stop the train is 6.197 x 10⁸ J.
Explanation:
Here, we are to solve for the work to stop a train. We are to connect work with a given mass and velocity.
To solve this, we are to use the work-energy principle. Since there is a net force of work doing on the train, the kinetic energy of the moving train will be equal to work done.
Therefore. we will be using the formula:
W = ΔKE
W = KE₂ - KE₁
W = (¹/₂mv²)₂ - (¹/₂mv²)₁
where
W is the work done on the train
m is the mass of the train
v is the velocity of the train
KE₂ is the final kinetic energy
KE₁ is the initial kinetic energy
For the given information
v = 54 m/s
m = 425,000 kg
W = ?
Solving the problem
So, let us solve for the work done on the train by using the work-energy formula.
Here, let us assume that the initial kinetic is zero.
W = ΔKE
W = KE₂ - KE₁
W = (¹/₂mv²)₂ - (¹/₂mv²)₁
Substitute the given information, we have:
W = ¹/₂(425000 kg)(54 m/s)²
W = 619,650,000 J or
W = 6.197 x 10⁸ J
Therefore, the work done on the train to stop it is 6.197 x 10⁸ J.
To learn more about this topic, just click on the following links:
- Relationship of work, energy and power
https://brainly.ph/question/160947
- Additional example with solution and answer
https://brainly.ph/question/2267052
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