cos0/sec0 - sin0/cot0 = cos0cot0-tan0/csc0

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27-10-2014
Math

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cos0/sec0 - sin0/cot0 = cos0cot0-tan0/csc0

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Donnskieidn Donnskieidn · Answer 1 · 2014-10-28T14:07:21+08:00

Donnskieidn Donnskieidn

28-10-2014

how to prove it?

cos0= to 1/cos0 if u will divide it by cos..it will become cos squared .. so cos*cos=cos squared.
minus..
cot0 =cos/sin0 .. so sin0 divide with the cot0 it will change to multiplication ryt? so the same as above.. it will become sin squared/cot
in trigonometric derivation
cos squared is = to cos0cot0 and the sin squared/cot is = to tan0/csc0

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