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Find two values of θ, 0° ≤ θ < 360°, that satisfy the given trigonometric equation.sin θ =  - [tex]sin θ = −
\sqrt{3} / 2


Sagot :

since you are to find the angle wherein sine is negative and that it is equal to -√3/2
remember that sine can only be negative if it is at the 3rd and 4th quadrant. and the angle based on the unit circle with sine being -√3/2 is 60degrees.. finding the two angles you'll have:
at the 3rd quadrant
180 + 60 = 240degrees
at the 4th quadrant
360 - 60 = 300degrees

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