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1. The sum of the digits of a two-digit number is 11. If we interchanged the digits then the new number formed is 45 less than the original. Find the original number and give it's working equation, given, solution, valuation, and final answer.

Sagot :

let x be the 1st digit and y be the 2nd digit
   10x+y be the original no. and 10y+x be the new no.

i)x+y=11
ii)10y+x=10x+y-45 it becomes -9x+9y=-45
    
   i)9(x+y)=11(9)=   9x+9y=99
                         +-9x+9y=-45
                                18y=54 
                                 18   18
                                   y=3
if y=3
i)x+y=11
 x+3=11
 x=11-3
 x=8        
 
 
 so the final ans. will be 83