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Knowing that tan α = 2, and that 180º < α < 270°, calculate the remaining trigonometric ratios of angle α.

Sagot :

since tangent is opposite over adjacent side then we may be able to get the hypotenuse or the longest side
hypotenuse = √(2²+1²
hypotenuse = √5
and because it is located somewhere in between 180 and 270 degrees then x and y values are both negative
tan α = 2
cot α = 1/2
sin α = -2/√5
cos α = -1/√5
sec α = -√5
csc α = -√5/2