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A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?

Sagot :

Area is given by the formula:
A = LW   
 where in this case L=height
L = 4/3W
since you are given the area then,
A =LW
192 = (4/3W)(W)
W² = (192)(3)/4
W² = 144
W = 12 in
substituting the value for W
L = 4/3W
L = 4/3(12)
L = 16 in
a for width
width = 4/3a


c=area=192 inch
a · 4/3a = 192
4/3a² = 192
a² = 144
√a² = √144
a = 12

The dimensions would be:
height: 12 inch
width: 4/3 (12) = 16inch