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given the doain of f(x)=4/3x+1 as
 domain is {3,6,9,12} what is the range.







Sagot :

domain are the values given for x and range for y
to find the range, all you have to do is substitute the given domain in the function
f(x) = 4/3x + 1
f(3) = (4/3)(3) + 1
f(3) = 4 + 1
f(3) = 5
f(6) = (4/3)(6) + 1
f(6) = 9 + 1
f(6) = 10
f(9) =  (4/3)(9) + 1
f(9) = 12 + 1
f(9) = 13
f(12) = (4/3)(12) + 1
f(12) = 16 + 1
f(12) = 17
Range is { 5, 10, 13, 17 }