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3x+5x(5)(9x)-65+73+6x=?

Sagot :

getting the value of x you'll have:
3x + 225x² - 65 + 73 + 6x =0
225x² + 9x + 8 = 0
using quadratic formula:
[tex]x = \frac{-b (+-) \sqrt{b^2-4ac} }{2a} [/tex]
[tex]x = \frac{-9 (+-) \sqrt{9^2-4(225)(8)} }{2(225)}[/tex]
notice that 9²-4(225)(8) = -7119
since it is inside the radical sign and possess a negative number 
then it makes the number imaginary and you'll have it as:
[tex]x = \frac{-9 (+-) \sqrt{-7119} }{450}[/tex]
[tex]x_1 = -0.02 + 0.1875i[/tex]
[tex]x_2 = -0.02-0.1875i[/tex]