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Find the roots of 4x squared-8x=0

Sagot :

by quadratic equation:
2,0
-b+-(plus and minus) the square root of b^2-4ac over 2a
= -(-8)+-(plus and minus) the square root of 64-4(4)(0)over 2(4)
=8+-(plus and minus) the square root of 64 over 8
= 8+8 over 8 or 8-8 over 8
=2 or 0

by equating...
it will become 4x(x-2)=0
then..
4x=0 , divide both side by 4 to get the value of x..the answer would be 0.
the other one is x-2=0 transpose 2 to the right side to get the value of x.. and it would be 2.
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