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How many different groups of 2000 people each could be formed from 2003 people?


Sagot :

Since this involves combination where there are 2003 people and 2000 people to be selected then we'll have it done using the combination formula taken to be as:
[tex]C = S = \frac{P}{r!} [/tex]
[tex] _{2003} C _{2000} = \frac{2003(2002)(2001)(2000)...(4)}{2000!} [/tex]
[tex] _{2003} C _{2000} = 1,337,337,001[/tex] combinations