first you need to know the number of moles of [tex]5.76 x 10 x^{22} [/tex] by divding it to avogadro's number ([tex]6.022x10 x^{23} [/tex])
[tex]5.76 x 10^{22} molecules x \frac{1mole}{6.022 x 10^{23}molecules } [/tex]
= 0.09 mole
find the molar mass of ammonia
N + 3H = molar mass of ammonia
(14.01) + (3)(1.008) = 17.034 g/mol
now, multiply 0.09 mole to 17.034 g/mol
[tex]0.09 mole NH_{3} x \frac{17.034grams}{1 mole NH_{3} } [/tex]
= 1.53306 grams
