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Answered

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answer this.
if f(x)=x³- 3x +1 show that f(u+1) =u+3u²-1.


Sagot :

The second function means that you just substitute the values inside f() on the variables on the first equation.

[tex]f(x)=x^3 -3x +1[/tex]

If x=u+1, then:
[tex]f(u+1)=(u+1)^3 -3(u+1) +1[/tex]

Expanding, we get: 
[tex]f(u+1)=(u^3 +3u^2+3u+1)-3u-3+1[/tex]

Simplifying this by combining like terms, we get:
[tex]f(u+1)=u^3+3u^2-1[/tex]

I have done some double-checking and this is the answer that I get. Maybe the u-3u^2-1 is a typo? 

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