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Sagot :
let x be the number
y be the other number
y = 5 + x ---equation 1
x + y = 49 ---equation 2
substitute eqn 1 to 2
x + y = 49
x + (5 + x) = 49
2x + 5 = 49
2x = 49 - 5
2x = 44
x = 22
substitute to equation 2
x + y = 49
22 + y = 49
y = 49 - 22
y = 27
y be the other number
y = 5 + x ---equation 1
x + y = 49 ---equation 2
substitute eqn 1 to 2
x + y = 49
x + (5 + x) = 49
2x + 5 = 49
2x = 49 - 5
2x = 44
x = 22
substitute to equation 2
x + y = 49
22 + y = 49
y = 49 - 22
y = 27
49 = N + N
the two numbers are 27 and 22
Solution:
y = 5 + x --- equation 1
x + y = 49 --- equation 2
substitute eqn 1 to 2
x + y = 49
x + (5 + x) = 49
2x + 5 = 49
2x = 49 - 5
2x = 44
x = 22
substitute to equation 2
x + y = 49
22 + y = 49
y = 49 - 22 --- answer
y = 27 --- other one answer
the two numbers are 27 and 22
Solution:
y = 5 + x --- equation 1
x + y = 49 --- equation 2
substitute eqn 1 to 2
x + y = 49
x + (5 + x) = 49
2x + 5 = 49
2x = 49 - 5
2x = 44
x = 22
substitute to equation 2
x + y = 49
22 + y = 49
y = 49 - 22 --- answer
y = 27 --- other one answer
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