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Sagot :
Why is this in Chemistry?
Anyway.
In order to solve system of equations using substitution, remember these two steps:
1. Isolate a variable that you think will have a simplified equation.
2. Plug-in this variable on the next equation.
Let's make the first system as an example.
On the first equation, let us isolate x on the left hand side.
[tex]2x+2y=2 \\\\ 2x=2-2y\\\\ x=1-y [/tex]
Now that we have a value for x, we substitute that on the second equation.
[tex]2(1-y)+3y=-2\\\\ 2-2y+3y=-2\\\\ y=-2-2=-4[/tex]
Plugging that value of y on the first equation, we get:
[tex]2x+2(-4)=2\\\\ 2x-8=2\\\\ 2x=10\\\\ x=5[/tex]
Do the same with the second problem. Hope that helps.
If you're having problems dealing with the second problem, don't hesitate to message me. :)
Anyway.
In order to solve system of equations using substitution, remember these two steps:
1. Isolate a variable that you think will have a simplified equation.
2. Plug-in this variable on the next equation.
Let's make the first system as an example.
On the first equation, let us isolate x on the left hand side.
[tex]2x+2y=2 \\\\ 2x=2-2y\\\\ x=1-y [/tex]
Now that we have a value for x, we substitute that on the second equation.
[tex]2(1-y)+3y=-2\\\\ 2-2y+3y=-2\\\\ y=-2-2=-4[/tex]
Plugging that value of y on the first equation, we get:
[tex]2x+2(-4)=2\\\\ 2x-8=2\\\\ 2x=10\\\\ x=5[/tex]
Do the same with the second problem. Hope that helps.
If you're having problems dealing with the second problem, don't hesitate to message me. :)
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