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a base angle of an isosceles triangle is 6 degree more than the vertex angle find the angles of the triangle


Sagot :

let x= angle at the vertex
    x+6=one base angle
   2x+12=two base angles
note:a triangle has a total of 180degrees interior angles
so your equation would be:
x+2x+12=180
3x=180-12
3x=168
x=56degrees - the angle at the vertex
x+6=62degrees for both the base angles